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AP Physics C: Mechanics Cheat Sheet


  • Acceleration due to Earth’s gravity: g=9.8 m/s2g = 9.8\ \text{m/s}^2
  • Universal gravitational constant: G=6.67×10−11 N⋅m2/kg2G = 6.67 \times 10^{-11}\ \text{N·m}^2/\text{kg}^2
  • Newton (force unit): 1 N=1 kg⋅m/s21\ \text{N} = 1\ \text{kg·m/s}^2
  • Joule (energy unit): 1 J=1 N⋅m=1 kg⋅m2/s21\ \text{J} = 1\ \text{N·m} = 1\ \text{kg·m}^2/\text{s}^2
  • Watt (power unit): 1 W=1 J/s1\ \text{W} = 1\ \text{J/s}
  • Radians in one revolution: 2π rad=360∘2\pi\ \text{rad} = 360^\circ
  • Earth’s radius (useful for orbits/escape): R⊕≈6.37×106 mR_\oplus \approx 6.37 \times 10^6\ \text{m}

  • Instantaneous velocity: v=dxdtv = \dfrac{dx}{dt}
  • Instantaneous acceleration: a=dvdt=d2xdt2a = \dfrac{dv}{dt} = \dfrac{d^2x}{dt^2}
  • Recover velocity and position by integration: Δv=∫a dt,Δx=∫v dt\Delta v = \displaystyle\int a\,dt,\qquad \Delta x = \displaystyle\int v\,dt
  • Acceleration depending on position (chain-rule trick): a=vdvdxa = v\dfrac{dv}{dx}
  • Average quantities: vˉ=ΔxΔt,aˉ=ΔvΔt\bar{v} = \dfrac{\Delta x}{\Delta t},\qquad \bar{a} = \dfrac{\Delta v}{\Delta t}
  • Slopes go down the list: slope of xx-tt is vv; slope of vv-tt is aa.
  • Areas go up the list: area under vv-tt is Δx\Delta x; area under aa-tt is Δv\Delta v.

Constant acceleration (the “Big Five”)

Section titled “Constant acceleration (the “Big Five”)”
  • Missing Δx\Delta x: vf=v0+atv_f = v_0 + at
  • Missing vfv_f: Δx=v0t+12at2\Delta x = v_0 t + \tfrac{1}{2}at^2
  • Missing v0v_0: Δx=vft−12at2\Delta x = v_f t - \tfrac{1}{2}at^2
  • Missing tt: vf2=v02+2aΔxv_f^2 = v_0^2 + 2a\Delta x
  • Missing aa: Δx=v0+vf2 t\Delta x = \dfrac{v_0 + v_f}{2}\,t

These hold only for constant acceleration; if aa varies, integrate instead.

  • Launch components: v0x=v0cos⁡θ,v0y=v0sin⁡θv_{0x} = v_0\cos\theta,\qquad v_{0y} = v_0\sin\theta
  • Position: x=v0xt,y=v0yt−12gt2x = v_{0x}t,\qquad y = v_{0y}t - \tfrac{1}{2}gt^2
  • Velocity: vx=v0x,vy=v0y−gtv_x = v_{0x},\qquad v_y = v_{0y} - gt
  • Level-ground range: R=v02sin⁡(2θ)gR = \dfrac{v_0^2\sin(2\theta)}{g} (max at θ=45∘\theta = 45^\circ)
  • Max height: h=v02sin⁡2θ2gh = \dfrac{v_0^2\sin^2\theta}{2g}
  • Time of flight: T=2v0sin⁡θgT = \dfrac{2v_0\sin\theta}{g}
  • If launch and landing heights differ, solve the yy quadratic instead of using these shortcuts.
  • Composition rule: v⃗A/C=v⃗A/B+v⃗B/C\vec{v}_{A/C} = \vec{v}_{A/B} + \vec{v}_{B/C} (swap subscripts to negate: v⃗A/B=−v⃗B/A\vec{v}_{A/B} = -\vec{v}_{B/A})

  • First law: if ∑F⃗=0\sum\vec{F} = 0, then a⃗=0\vec{a} = 0.
  • Second law: ∑F⃗=ma⃗\sum\vec{F} = m\vec{a}, by components ∑Fx=max,∑Fy=may\sum F_x = ma_x,\quad \sum F_y = ma_y.
  • Third law: F⃗A on B=−F⃗B on A\vec{F}_{A\text{ on }B} = -\vec{F}_{B\text{ on }A}.
  • General (momentum) form: F⃗net=dp⃗dt=mdv⃗dt\vec{F}_{\text{net}} = \dfrac{d\vec{p}}{dt} = m\dfrac{d\vec{v}}{dt} for constant mass.
  • Weight: Fg=mgF_g = mg (points down)
  • Normal force: perpendicular to surface; solve from the perpendicular equation, never assume FN=mgF_N = mg.
  • Static friction: 0≤fs≤μsFN0 \le f_s \le \mu_s F_N (max at impending slip)
  • Kinetic friction: fk=μkFNf_k = \mu_k F_N, usually μs>μk\mu_s > \mu_k
  • Hooke’s law (spring): F⃗s=−kx⃗\vec{F}_s = -k\vec{x}
  • Linear drag: F⃗d=−bv⃗\vec{F}_d = -b\vec{v}; terminal velocity vt=mg/bv_t = mg/b
  • Falling from rest with linear drag (down positive): v(t)=vt(1−e−bt/m),vt=mgbv(t)=v_t\left(1-e^{-bt/m}\right),\qquad v_t=\dfrac{mg}{b}
  • Quadratic drag: Fd∝v2F_d\propto v^2 opposite the velocity (use the model stated in the problem)
  • Weight components: mgsin⁡θmg\sin\theta (along plane), mgcos⁡θmg\cos\theta (perpendicular)
  • Normal force on incline: FN=mgcos⁡θF_N = mg\cos\theta
  • Frictionless acceleration down plane: a=gsin⁡θa = g\sin\theta
  • Maximum angle before sliding: tan⁡θmax⁡=μs\tan\theta_{\max} = \mu_s
  • Atwood machine: a=(m2−m1)gm1+m2,T=2m1m2m1+m2ga = \dfrac{(m_2 - m_1)g}{m_1 + m_2},\qquad T = \dfrac{2m_1 m_2}{m_1 + m_2}g
  • Apparent weight (up positive): FN=m(g+a)F_N = m(g + a)
  • Centripetal acceleration: ac=v2r=ω2ra_c = \dfrac{v^2}{r} = \omega^2 r
  • Radial Newton’s second law: ∑Fr=mv2r\sum F_r = m\dfrac{v^2}{r}
  • Flat-curve max speed: vmax⁡=μsgrv_{\max} = \sqrt{\mu_s g r}
  • Frictionless banked curve: tan⁡θ=v2rg,v=rgtan⁡θ\tan\theta = \dfrac{v^2}{rg},\qquad v = \sqrt{rg\tan\theta}
  • Minimum speed at top of vertical loop: vtop=grv_{\text{top}} = \sqrt{gr}
  • Nonuniform: ar=v2r,at=dvdta_r = \dfrac{v^2}{r},\qquad a_t = \dfrac{dv}{dt}
  • Center-of-mass dynamics: ∑F⃗ext=Ma⃗cm\sum\vec{F}_{\text{ext}} = M\vec{a}_{\text{cm}} (internal forces cancel in pairs)
  • Pseudo-force in an accelerating frame: F⃗pseudo=−ma⃗frame\vec{F}_{\text{pseudo}} = -m\vec{a}_{\text{frame}}
  • Effective gravity in an accelerating frame: g⃗eff=g⃗−a⃗frame\vec{g}_{\text{eff}}=\vec{g}-\vec{a}_{\text{frame}}

  • Constant force: W=F⃗⋅Δr⃗=FΔrcos⁡θW = \vec{F}\cdot\Delta\vec{r} = F\Delta r\cos\theta
  • Variable force (line integral): W=∫CF⃗⋅dr⃗W = \displaystyle\int_C \vec{F}\cdot d\vec{r}, in 1D W=∫xixfFx dxW = \displaystyle\int_{x_i}^{x_f} F_x\,dx
  • Sign of work: positive for 0≤θ<90∘0\le\theta<90^\circ, negative for 90∘<θ≤180∘90^\circ<\theta\le180^\circ, zero at θ=90∘\theta = 90^\circ (a perpendicular force does no work).

Kinetic energy and the work-energy theorem

Section titled “Kinetic energy and the work-energy theorem”
  • Kinetic energy: K=12mv2K = \tfrac{1}{2}mv^2
  • Work-energy theorem: Wnet=ΔKW_{\text{net}} = \Delta K
  • Useful identity: K=p22mK = \dfrac{p^2}{2m}
  • Conservative force from potential: Fx=−dUdxF_x = -\dfrac{dU}{dx}, in 3D F⃗=−∇U\vec{F} = -\nabla U
  • Defining relation: Wcons=−ΔUW_{\text{cons}} = -\Delta U, and ∮F⃗⋅dr⃗=0\displaystyle\oint\vec{F}\cdot d\vec{r} = 0 for conservative forces
  • Gravity near Earth: Ug=mgyU_g = mgy
  • Universal gravitation: Ug(r)=−GMmrU_g(r) = -\dfrac{GMm}{r}
  • Spring: Us=12kx2U_s = \tfrac{1}{2}kx^2
  • Total mechanical energy: Emech=K+UE_{\text{mech}}=K+U
  • Only conservative forces: Ki+Ui=Kf+UfK_i + U_i = K_f + U_f
  • With nonconservative work: Ki+Ui+Wnc=Kf+UfK_i + U_i + W_{\text{nc}} = K_f + U_f, equivalently Wnc=ΔEmechW_{\text{nc}} = \Delta E_{\text{mech}}
  • Energy diagrams: equilibrium where dUdx=0\dfrac{dU}{dx} = 0; stable if d2Udx2>0\dfrac{d^2U}{dx^2} > 0, unstable if d2Udx2<0\dfrac{d^2U}{dx^2} < 0, neutral if d2Udx2=0\dfrac{d^2U}{dx^2}=0; turning points where E=U(x)E = U(x).
  • Instantaneous power: P=dWdt=F⃗⋅v⃗P = \dfrac{dW}{dt} = \vec{F}\cdot\vec{v}
  • Average power: Pˉ=ΔEΔt\bar{P} = \dfrac{\Delta E}{\Delta t}

  • Momentum: p⃗=mv⃗\vec{p} = m\vec{v}
  • Newton’s second law (general): F⃗net=dp⃗dt\vec{F}_{\text{net}} = \dfrac{d\vec{p}}{dt}
  • Impulse: J⃗=∫titfF⃗net dt=Δp⃗\vec{J} = \displaystyle\int_{t_i}^{t_f}\vec{F}_{\text{net}}\,dt = \Delta\vec{p} (area under an FF-tt graph)
  • Average force: F⃗avg=J⃗Δt=Δp⃗Δt\vec{F}_{\text{avg}} = \dfrac{\vec{J}}{\Delta t} = \dfrac{\Delta\vec{p}}{\Delta t}
  • Product rule: ddt(mv⃗)=mdv⃗dt+v⃗dmdt\dfrac{d}{dt}(m\vec v)=m\dfrac{d\vec v}{dt}+\vec v\dfrac{dm}{dt}
  • In 1D, keep signs with: Fext=mdvdt+vdmdtF_{\text{ext}}=m\dfrac{dv}{dt}+v\dfrac{dm}{dt} for the chosen system.
  • Object collecting mass with no incoming velocity in the direction of motion: mdvdt+vdmdt=0m\dfrac{dv}{dt}+v\dfrac{dm}{dt}=0
  • Ideal rocket in empty space: dv=−udmmdv=-u\dfrac{dm}{m}, so Δv=uln⁡(m0mf)\Delta v=u\ln\left(\dfrac{m_0}{m_f}\right)
  • If ∑F⃗ext=0\sum\vec{F}_{\text{ext}} = 0 (or its impulse is negligible): P⃗i=P⃗f\vec{P}_i = \vec{P}_f
  • Conserve components separately in 2D: ∑px,i=∑px,f,∑py,i=∑py,f\sum p_{x,i} = \sum p_{x,f},\qquad \sum p_{y,i} = \sum p_{y,f}
  • Discrete: r⃗cm=1M∑imir⃗i\vec{r}_{\text{cm}} = \dfrac{1}{M}\displaystyle\sum_i m_i\vec{r}_i
  • Continuous: r⃗cm=1M∫r⃗ dm\vec{r}_{\text{cm}} = \dfrac{1}{M}\displaystyle\int\vec{r}\,dm
  • System momentum: P⃗sys=Mv⃗cm\vec{P}_{\text{sys}} = M\vec{v}_{\text{cm}}
  • Center of mass velocity: v⃗cm=1M∑imiv⃗i\vec v_{\text{cm}}=\dfrac{1}{M}\displaystyle\sum_i m_i\vec v_i
  • Elastic: momentum and kinetic energy both conserved, P⃗i=P⃗f, Ki=Kf\vec{P}_i = \vec{P}_f,\ K_i = K_f
  • Perfectly inelastic (stick together): m1v⃗1i+m2v⃗2i=(m1+m2)v⃗fm_1\vec{v}_{1i} + m_2\vec{v}_{2i} = (m_1+m_2)\vec{v}_f (maximum KE loss)
  • 1D elastic relative-speed reversal: v1i−v2i=−(v1f−v2f)v_{1i} - v_{2i} = -(v_{1f} - v_{2f})
  • 1D elastic final velocities:
v1f=m1−m2m1+m2v1i+2m2m1+m2v2iv_{1f} = \frac{m_1-m_2}{m_1+m_2}v_{1i} + \frac{2m_2}{m_1+m_2}v_{2i} v2f=2m1m1+m2v1i+m2−m1m1+m2v2iv_{2f} = \frac{2m_1}{m_1+m_2}v_{1i} + \frac{m_2-m_1}{m_1+m_2}v_{2i}
  • Equal masses in 1D elastic collision exchange velocities.
  • CM-frame energy lost when objects stick: ΔElost=Kinitial′\Delta E_{\text{lost}}=K'_{\text{initial}}

  • Definitions: ω=dθdt,α=dωdt=d2θdt2\omega = \dfrac{d\theta}{dt},\qquad \alpha = \dfrac{d\omega}{dt} = \dfrac{d^2\theta}{dt^2}
  • Constant α\alpha: ωf=ωi+αt,Δθ=ωit+12αt2,Δθ=ωft−12αt2\omega_f = \omega_i + \alpha t,\quad \Delta\theta = \omega_i t + \tfrac{1}{2}\alpha t^2,\quad \Delta\theta = \omega_f t - \tfrac{1}{2}\alpha t^2
  • Constant α\alpha without time: ωf2=ωi2+2αΔθ,Δθ=ωi+ωf2t\omega_f^2 = \omega_i^2 + 2\alpha\Delta\theta,\qquad \Delta\theta=\dfrac{\omega_i+\omega_f}{2}t
  • Linear-angular links: s=rθ,vt=rω,at=rα,ar=rω2s = r\theta,\quad v_t = r\omega,\quad a_t = r\alpha,\quad a_r = r\omega^2
  • Vector definition: τ⃗=r⃗×F⃗\vec{\tau} = \vec{r}\times\vec{F}
  • Magnitude: τ=rFsin⁡θ=Fr⊥=rF⊥\tau = rF\sin\theta = F r_\perp = r F_\perp
  • Sign convention: counterclockwise positive, clockwise negative.
  • Point masses: I=∑imiri2I = \displaystyle\sum_i m_i r_i^2
  • Continuous body: I=∫r2 dmI = \displaystyle\int r^2\,dm
  • Point mass: I=mr2I = mr^2
  • Thin hoop about center: I=MR2I = MR^2
  • Solid disk/cylinder about center: I=12MR2I = \tfrac{1}{2}MR^2
  • Solid sphere about diameter: I=25MR2I = \tfrac{2}{5}MR^2
  • Thin rod about center: I=112ML2I = \tfrac{1}{12}ML^2
  • Thin rod about end: I=13ML2I = \tfrac{1}{3}ML^2
  • Parallel-axis: I=Icm+Md2I = I_{\text{cm}} + Md^2
  • Perpendicular-axis (flat lamina only): Iz=Ix+IyI_z = I_x + I_y
  • Fixed axis: ∑τ=Iα\sum\tau = I\alpha
  • About the center of mass: ∑τ⃗cm=Icmα⃗\sum\vec{\tau}_{\text{cm}} = I_{\text{cm}}\vec{\alpha}, with ∑F⃗ext=Ma⃗cm\sum\vec{F}_{\text{ext}} = M\vec{a}_{\text{cm}}
  • Static equilibrium: ∑F⃗=0\sum\vec{F} = 0 and ∑τ⃗=0\sum\vec{\tau} = 0 (in equilibrium, torque is zero about every axis—pivot at an unknown force).
  • Massive pulley Atwood setup: (T2−T1)R=Iα,a=Rα(T_2-T_1)R=I\alpha,\qquad a=R\alpha
  • Constraints: vcm=Rω,acm=Rαv_{\text{cm}} = R\omega,\qquad a_{\text{cm}} = R\alpha
  • Acceleration down an incline: a=gsin⁡θ1+Icm/MR2a = \dfrac{g\sin\theta}{1 + I_{\text{cm}}/MR^2} (sphere fastest, then disk, then hoop)
  • If Icm=βMR2I_{\text{cm}}=\beta MR^2, then a=gsin⁡θ1+β,f=β1+βMgsin⁡θa=\dfrac{g\sin\theta}{1+\beta},\qquad f=\dfrac{\beta}{1+\beta}Mg\sin\theta
  • Special rolling inclines: sphere a=57gsin⁡θa=\tfrac57g\sin\theta, disk/cylinder a=23gsin⁡θa=\tfrac23g\sin\theta, hoop a=12gsin⁡θa=\tfrac12g\sin\theta

  • Rotational kinetic energy: Krot=12Iω2K_{\text{rot}} = \tfrac{1}{2}I\omega^2
  • Total (translation + rotation): K=12Mvcm2+12Icmω2K = \tfrac{1}{2}Mv_{\text{cm}}^2 + \tfrac{1}{2}I_{\text{cm}}\omega^2
  • Rolling speed from height: v=2gh1+Icm/MR2v = \sqrt{\dfrac{2gh}{1 + I_{\text{cm}}/MR^2}}
  • For Icm=βMR2I_{\text{cm}}=\beta MR^2, rolling speed from height becomes v=2gh1+βv=\sqrt{\dfrac{2gh}{1+\beta}}
  • Rotational work: Wrot=∫τ dθW_{\text{rot}} = \displaystyle\int\tau\,d\theta, with Wnet,rot=ΔKrotW_{\text{net,rot}} = \Delta K_{\text{rot}}
  • Rotational power: P=τω=τ⃗⋅ω⃗P = \tau\omega = \vec{\tau}\cdot\vec{\omega}
  • Particle: L⃗=r⃗×p⃗,L=rpsin⁡θ\vec{L} = \vec{r}\times\vec{p},\qquad L = rp\sin\theta (depends on the chosen origin)
  • Rigid body (symmetry axis): L⃗=Iω⃗\vec{L} = I\vec{\omega}
  • Torque as rate of change: ∑τ⃗ext=dL⃗dt\sum\vec{\tau}_{\text{ext}} = \dfrac{d\vec{L}}{dt}
  • Conservation (zero external torque): L⃗i=L⃗f\vec{L}_i = \vec{L}_f, i.e. Iiωi=IfωfI_i\omega_i = I_f\omega_f
  • Angular impulse: ∫titfτ⃗ext dt=ΔL⃗\displaystyle\int_{t_i}^{t_f}\vec{\tau}_{\text{ext}}\,dt = \Delta\vec{L}
  • Central force (e.g. gravity): torque about center is zero, so LL is conserved; areal velocity dAdt=L2m\dfrac{dA}{dt} = \dfrac{L}{2m} is constant (Kepler’s second law).
  • Periapsis/apoapsis angular momentum: rpvp=ravar_pv_p=r_av_a

Note: LL is conserved whenever external torque vanishes, but KrotK_{\text{rot}} need not be (sticking/merging lowers it; pulling mass inward raises it).


  • Condition: a=−ω2xa = -\omega^2 x, equivalently d2xdt2+ω2x=0\dfrac{d^2x}{dt^2} + \omega^2 x = 0
  • General solution: x(t)=Acos⁡(ωt+ϕ)x(t) = A\cos(\omega t + \phi)
  • Velocity and acceleration: v(t)=−Aωsin⁡(ωt+ϕ),a(t)=−Aω2cos⁡(ωt+ϕ)v(t) = -A\omega\sin(\omega t + \phi),\qquad a(t) = -A\omega^2\cos(\omega t + \phi)
  • Amplitude from initial conditions: A=x02+(v0/ω)2A = \sqrt{x_0^2 + (v_0/\omega)^2}
  • Phase from initial conditions: tan⁡ϕ=−v0ωx0\tan\phi=-\dfrac{v_0}{\omega x_0} (check the quadrant)
  • Maxima: vmax⁡=Aω,amax⁡=Aω2v_{\max} = A\omega,\qquad a_{\max} = A\omega^2
  • Speed vs position: v(x)=±ωA2−x2v(x) = \pm\omega\sqrt{A^2 - x^2}
  • Period and frequency: ω=2πf=2πT\omega = 2\pi f = \dfrac{2\pi}{T}
  • Mass-spring: ω=km,T=2πmk\omega = \sqrt{\dfrac{k}{m}},\qquad T = 2\pi\sqrt{\dfrac{m}{k}} (independent of amplitude)
  • Springs in parallel: keff=k1+k2k_{\text{eff}} = k_1 + k_2 (stiffer)
  • Springs in series: 1keff=1k1+1k2\dfrac{1}{k_{\text{eff}}} = \dfrac{1}{k_1} + \dfrac{1}{k_2} (softer)
  • General spring geometry: match total spring energy to U=12keffx2U=\tfrac12k_{\text{eff}}x^2
  • Simple pendulum (small angle): ω=gL,T=2πLg\omega = \sqrt{\dfrac{g}{L}},\qquad T = 2\pi\sqrt{\dfrac{L}{g}}
  • Physical pendulum (II about the pivot, dd to the CM): T=2πImgdT = 2\pi\sqrt{\dfrac{I}{mgd}}
  • Floating object: ω=ρliqgρobjh\omega=\sqrt{\dfrac{\rho_{\text{liq}}g}{\rho_{\text{obj}}h}}
  • U-tube liquid oscillator: ω=2gL,T=2πL2g\omega=\sqrt{\dfrac{2g}{L}},\qquad T=2\pi\sqrt{\dfrac{L}{2g}}
  • Small oscillations near a potential minimum: keff=U′′(x0),ω=U′′(x0)mk_{\text{eff}} = U''(x_0),\qquad \omega = \sqrt{\dfrac{U''(x_0)}{m}}
  • Total energy: E=K+U=12mv2+12kx2=12kA2=12mvmax⁡2E = K + U = \tfrac{1}{2}mv^2 + \tfrac{1}{2}kx^2 = \tfrac{1}{2}kA^2 = \tfrac{1}{2}mv_{\max}^2
  • Damped oscillator: md2xdt2+bdxdt+kx=0m\dfrac{d^2x}{dt^2} + b\dfrac{dx}{dt} + kx = 0
  • Critical damping coefficient: bc=2mk=2mω0b_c = 2\sqrt{mk} = 2m\omega_0
  • Underdamped (b<bcb < b_c) oscillates with decaying amplitude e−(b/2m)te^{-(b/2m)t}; critically damped returns fastest with no overshoot; overdamped returns slowly.
  • Resonance occurs when the driving frequency ωd\omega_d is near the natural frequency ω0=k/m\omega_0 = \sqrt{k/m}; lighter damping gives a taller, narrower peak.

  • Force magnitude: Fg=GMmr2F_g = \dfrac{GMm}{r^2} (attractive, along the line joining the masses)
  • Gravitational field / surface gravity: g=GMR2g = \dfrac{GM}{R^2}
  • Potential energy (zero at infinity): Ug(r)=−GMmrU_g(r) = -\dfrac{GMm}{r}
  • Circular orbit (gravity supplies the centripetal force): GMmr2=mv2r ⇒ vorbit=GMr\dfrac{GMm}{r^2} = \dfrac{mv^2}{r}\ \Rightarrow\ v_{\text{orbit}} = \sqrt{\dfrac{GM}{r}}
  • Circular orbit period: T=2πr3GMT=2\pi\sqrt{\dfrac{r^3}{GM}}
  • Escape speed: vesc=2GMR=2gRv_{\text{esc}} = \sqrt{\dfrac{2GM}{R}} = \sqrt{2gR}
  • Kepler’s third law: T2=4π2GMa3T^2 = \dfrac{4\pi^2}{GM}a^3, where aa is the semi-major axis.
  • Around the Sun using years and AU: T2=a3T^2=a^3
  • Orbital mechanical energy: E=−GMm2aE=-\dfrac{GMm}{2a}
  • Angular momentum is conserved in any orbit (central force), so vprp=varav_p r_p = v_a r_a at perihelion/periapsis and aphelion/apoapsis.
  • Areal velocity: dAdt=L2m\dfrac{dA}{dt}=\dfrac{L}{2m}

Most Common AP Physics C: Mechanics Mistakes

Section titled “Most Common AP Physics C: Mechanics Mistakes”
  1. Using the Big Five kinematics equations when acceleration is not constant—integrate instead.
  2. Assuming FN=mgF_N = mg on inclines, in elevators, or with extra applied forces.
  3. Treating fs=μsFNf_s = \mu_s F_N always; that is only the maximum static friction.
  4. Forgetting that a perpendicular force (normal, tension in circular motion) does zero work.
  5. Mixing momentum and energy conservation in the wrong stage of a collision (e.g. the ballistic pendulum: momentum during impact, energy during the swing).
  6. Using τ=rF\tau = rF without the sin⁡θ\sin\theta (lever arm).
  7. Computing II about the wrong axis—remember the parallel-axis theorem.
  8. Assuming KrotK_{\text{rot}} is conserved when only LL is (inelastic rotational collisions lose energy).
  9. Sign and quadrant errors when finding the SHM phase constant ϕ\phi from arctan⁡\arctan alone.
  10. Forgetting the negative sign in Ug=−GMm/rU_g = -GMm/r for universal gravitation.

  1. Identify the system and draw a free-body (or extended-body) diagram.
  2. Decide the right tool: kinematics, Newton’s laws, energy, momentum, or rotation.
  3. Choose axes and a sign convention that match the geometry or expected acceleration.
  4. For energy/momentum problems, check whether the relevant quantity is conserved before writing equations.
  5. Solve symbolically first, then substitute numbers with units.
  6. Check limiting cases (zero friction, equal masses, small angle) and confirm the sign and magnitude make physical sense.
  7. If given a graph, always remember that the slope corresponds to the derivative/division, and the area under the curve correlates to integration/multiplication.

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